9n^2=333

Solution for 9n^2=333 equation:

9n^2=333

We move all terms to the left:

9n^2-(333)=0

a = 9; b = 0; c = -333;
Δ = b2-4ac
Δ = 02-4·9·(-333)
Δ = 11988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11988}=\sqrt{324*37}=\sqrt{324}*\sqrt{37}=18\sqrt{37}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{37}}{2*9}=\frac{0-18\sqrt{37}}{18}
=-\frac{18\sqrt{37}}{18}
=-\sqrt{37}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{37}}{2*9}=\frac{0+18\sqrt{37}}{18}
=\frac{18\sqrt{37}}{18}
=\sqrt{37}
$